20x^2+5=185

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Solution for 20x^2+5=185 equation:



20x^2+5=185
We move all terms to the left:
20x^2+5-(185)=0
We add all the numbers together, and all the variables
20x^2-180=0
a = 20; b = 0; c = -180;
Δ = b2-4ac
Δ = 02-4·20·(-180)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*20}=\frac{-120}{40} =-3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*20}=\frac{120}{40} =3 $

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